-50x^2+600x-1000=0

Solution for -50x^2+600x-1000=0 equation:

-50x^2+600x-1000=0

a = -50; b = 600; c = -1000;
Δ = b2-4ac
Δ = 6002-4·(-50)·(-1000)
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-400}{2*-50}=\frac{-1000}{-100}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+400}{2*-50}=\frac{-200}{-100}
=+2
$